You are currently browsing the tag archive for the ‘Separability’ tag.
Last time: Theorem 21 (Groves–Manning–Osin): If is hyperbolic rel
then there exists a finite subset
such that if
then
(a) is injective;
(b) is hyperbolic rel
.
Theorem 22 (Gromov, Olshanshkii, Delzant): If is hyperbolic relative to the infinite cyclic
then there is a
such that for all
there exists a
hyperbolic such that
for each
.
The proof is an easy application of Groves–Manning–Osin.
Definition: If (infinite cyclic) is malnormal then we say
are independent. A group G is omnipotent if for every independent
there exists a
such that for all
there exists a homomorphism $\phi$ from
to a finite group such that
for all
.
Omnipotence strengthens residual finiteness for torsionfree groups.
Exercise 29: If every hyperbolic group is residually finite then every hyperbolic group is omnipotent.
We’ll finish off by talking about a similar theorem of Agol–Groves–Manning. I’m going to seem a little cavalier about torsion. This is OK. In fact, if every hyperbolic group is residually finite then every hyperbolic group is virtually torsionfree.
Theorem 22 (Agol–Groves–Manning): If every hyperbolic group is residually finite then every quasi-convex subgroup of any hyperbolic group
is separable.
Let . The idea is to Dehn fill
to get a new hyperbolic group
in which the image
is finite and
. If we could do this, we would be done by residual finiteness. This works if
is malnormal. But it probably isn’t. Fortunately, we can quantify how far
is from being malnormal:
Definition: The height of is the maximal
such that there are distinct cosets
such that the intersection
is infinite.
H is height iff
is finite. In a torsionfree group,
is height
iff
is malnormal.
Theorem 23 (Gitik, Mitra, Rips, Sageev): A quasiconvex subgroup of a hyperbolic group has finite height.
Agol, Groves and Manning are able to prove:
Theorem 24: Let be a (torsionfree) residually finite hyperbolic group, and
a quasiconvex subgroup of height
. Let
. Then is an epimorphism
to a hyperbolic group such that
(i) is quasiconvex in
;
(ii) ;
(iii) has height
.
The idea of the proof of Theorem 24 is to Dehn fill a finite index subgroup of a maximal infinite intersection of conjugates of . Theorem 22 is an easy consequence.
Lemma 29: Suppose is a finite set of infinite degree elvations and
is compact. Then for all sufficiently large
, there exists an intermediate covering
such that
(a) embeds in
(b) every descends to an elevation
of degree
(c) the are pairwise distinct
Proof: We claim that the images of never share an infinite ray (a ray is an isometric embedding of
). Neither do two ends of the same elevation
. Let’s claim by passing to the universal cover of
, a tree
.
For each , lift
to a map
. If
and
share an infinite ray then there exists
such that
and
overlay in an infinite ray. The point is that
correspond to cosets
and
. But this implies that
This implies that . So
. A similar argument implies that the two ends of
do not overlap in an infinite ray. This proves the claim.
Let be the core of
. Enlarging
if necessary, we can assume that
(i) ;
(ii) is a connected subgraph;
(iii) for each , for some
,
;
(iv) for each ,
.
For each identifying
with
so that
is identified with
and
is identified with
. Let
For all sufficiently large ,
Now, the restriction of factors through
, where
. This is a finite-to-one immersion, so, by theorem 5, we can complete it to a finite-sheeted covering map as required.
Theorem 19: is LERF.
Recall the set-up from the previous lecture. We built a graph of spaces for
.
Proof: Let be finitely generated. Let
be the corresponding covering space of
and let
be compact. Because
is finitely generated, there exists a subgraph of spaces
such that
. We can take
large enough so that
. We can enlarge
so that it contains every finite-degree edge space of
. Also enlarge
so that
for any . For each
let
and let
incident edge map of infinite degree
.
Applying lemma 29 to , for some large
, set
. (Here we use the fact that vertex groups of
are finitely generated)
Define as follows:
For each
, the edge space is the
that the lemma produced from the corresponding
.
Now, by construction, can be completed to a graph of spaces
so that the map
factors through and
embeds. Let
be identical to
except with +’s and -’s exchanged. Clearly
satisfies Stallings condition, as required.
Agol-Groves-Manning’s Theorem predicts that, for every word-hyperbolic group we can easily construct, every quasiconvex subgroup is separable (otherwise, we would find a non-residually finite hyperbolic group!).
In this section, we use graphs of groups to build new hyperbolic groups:
Combination Theorem (Bestvina & Feighn): If is a malnormal subgroup of hyperbolic groups
, then
is hyperbolic.
Recall: is called a malnormal subgroup of
if it satisfies: if
, then
.
For a proof, see M. Bestvina and M. Feighn, “A combination theorem for negatively curved groups”, J. Differential Geom., 35 (1992), 85–101.
Example: Let be free,
not a proper power. By Lemma 11,
is malnormal, so
is hyperbolic. As a special case, if
is closed surface of even genus
, considered as the connected sum of two copies of the closed surface of genus
, then by Seifert-van Kampen Theorem,
for some
.
Question: (a) Which subgroups of are quasiconvex? (b) Which subgroups of
are separable?
We will start by trying to answer (b). The following is an outline of the argument: Let be a finite graph so that
, let
be two copies of
. Realize
as maps
, where
. Let
be the graph of spaces with vertex spaces
, edge space
, and edge maps
. Then clearly,
, and finitely generated subgroups
are in correspondence with covering spaces
. We can then use similar technique to sections 27 and 28.
Let us now make a few remarks about elevations of loops. Let be a loop in some space
, i.e.,
and
. Consider an elevation of
:

The conjugacy classes of subgroups of are naturally in bijection with
. The degree of the elevation is equal to the degree of the covering map
.
Definition: Suppose is a covering map and
is an intermediate covering space, i.e.,
factors through
, and we have a diagram

If and
are elevations of
and the diagram commutes, then we say that
descends to
.
Let be a finite graph,
a finitely generated subgroup and
a loop. Let
be a covering space corresponding to
.
Lemma 29: Consider a finite collection of elevations of
to
, each of infinite degree. Let
be compact. Then for all sufficiently large
, there exists an intermediate, finite-sheeted covering space
satisfying: (a)
embeds in
; (b) every
descends to an elevation
of degree exactly
; (c) these
are pairwise distinct.


Recent Comments