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Last time: Theorem 21 (Groves–Manning–Osin): If is hyperbolic rel
then there exists a finite subset
such that if
then
(a) is injective;
(b) is hyperbolic rel
.
Theorem 22 (Gromov, Olshanshkii, Delzant): If is hyperbolic relative to the infinite cyclic
then there is a
such that for all
there exists a
hyperbolic such that
for each
.
The proof is an easy application of Groves–Manning–Osin.
Definition: If (infinite cyclic) is malnormal then we say
are independent. A group G is omnipotent if for every independent
there exists a
such that for all
there exists a homomorphism $\phi$ from
to a finite group such that
for all
.
Omnipotence strengthens residual finiteness for torsionfree groups.
Exercise 29: If every hyperbolic group is residually finite then every hyperbolic group is omnipotent.
We’ll finish off by talking about a similar theorem of Agol–Groves–Manning. I’m going to seem a little cavalier about torsion. This is OK. In fact, if every hyperbolic group is residually finite then every hyperbolic group is virtually torsionfree.
Theorem 22 (Agol–Groves–Manning): If every hyperbolic group is residually finite then every quasi-convex subgroup of any hyperbolic group
is separable.
Let . The idea is to Dehn fill
to get a new hyperbolic group
in which the image
is finite and
. If we could do this, we would be done by residual finiteness. This works if
is malnormal. But it probably isn’t. Fortunately, we can quantify how far
is from being malnormal:
Definition: The height of is the maximal
such that there are distinct cosets
such that the intersection
is infinite.
H is height iff
is finite. In a torsionfree group,
is height
iff
is malnormal.
Theorem 23 (Gitik, Mitra, Rips, Sageev): A quasiconvex subgroup of a hyperbolic group has finite height.
Agol, Groves and Manning are able to prove:
Theorem 24: Let be a (torsionfree) residually finite hyperbolic group, and
a quasiconvex subgroup of height
. Let
. Then is an epimorphism
to a hyperbolic group such that
(i) is quasiconvex in
;
(ii) ;
(iii) has height
.
The idea of the proof of Theorem 24 is to Dehn fill a finite index subgroup of a maximal infinite intersection of conjugates of . Theorem 22 is an easy consequence.
We still need to convince ourselves of some basic facts about the previous lecture, for example is the map injective?
Example: Cut the sphere along the equator. Then the diagram we have is
Definition: Let be a connected graph (i.e. a 1-dimensional CW-complex). For each vertex
(resp. edge
) let
(resp.
) be a group. If
are vertices adjoining an edge e then let
be an injective homomorphism. This data determines a graph of groups
.
We say that has:
- underlying graph
- vertex groups
- edge groups
- edge maps
Similarly, we have:
Definition: Let be a connected graph. For each vertex
(resp.
) let
(resp.
) be a connected CW-complex. If
adjoin
let
be
-injective continuous maps. This data determines a graph of spaces
. It has underlying graph
, vertex spaces
, edge spaces
, etc. The graph of spaces
determines a space as follows: define
where for
. We say that
is a graph-of-spaces structure (or decomposition) for
.
Remark: There is a natural map (by collapsing all the edge and vertex spaces).
Given any graph of groups we can construct a graph of spaces
with underlying graph
by assigning
and realizing the edge maps as continuous maps
. We write
for
. This is well-defined up to homotopy equivalence.
Definition: The fundamental group of is just
Examples:
- If
then
- If
then - Let
be an embedded multicurve (disjoint union of circles) inside a surface. Cutting along
decomposes
into a graph of spaces and
into a graph of groups.
Note: The edge maps of are only defined up to free (i.e. unbased) homotopy. Translated to
, this means that only the conjugacy class of
in
matters.
Remark: The map induces a surjection
Here’s a way to construct a graph of groups. Let’s suppose acts on a tree
without edge inversions (we can do this by subdividing edges if necessary). Let
. The group
acts diagonally on
The quotient
has a structure of a graph of spaces. The underlying graph is
and there is a natural map
.
Let be a vertex below
. The preimage of
is just
where
is the stabilizer of
. Similarly, for
below
, the preimage of
is
If adjoins
then
so the edge map
is a covering map and therefore
-injective. We have defined a graph of spaces
and
since
is simply connected.
Applying to everything, we have a graph of groups
. Its underlying graph is
. Its vertex groups are the vertex stabilizers of
, its edge groups are the edge stabilizers, and the edge maps are the inclusions. Also,
.
Question for next time: Does every graph of groups arise in this way?

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